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With two hands you hold a cone motionles...

With two hands you hold a cone motionless upside doen , as shown in figure The mass of the cone is `(m = 1 kg)` and the coefficient of static friction between you fingers and the cone is `(mu = 0.5)` what is the minimum normal force you must applywith each hand in order to hold up the cone? Consider only translational equilibruim

Text Solution

Verified by Experts

The correct Answer is:
50 N

`mg+2Ncos 53^(@)=2muN cos 37^(@)`
`mg +2N(3)/(5)=2mu(4)/(5)N`
`rArr mg =((8)/(5)-(6)/(5))N" "N=50` newton
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