Home
Class 12
PHYSICS
In the figure, magnetic energy stored in...

In the figure, magnetic energy stored in the coil is `

A

`4 pi xx 10^(-2) N,+y`

B

`4 pi xx 10^(-2) N.-y`

C

`4 sqrt(3) pi xx 10^(-2) + y`

D

`4 sqrt(3) pi xx 10^(-2) N,-y`

Text Solution

Verified by Experts

The correct Answer is:
D

Force on each part of ring is shown in figure

`= 20.12 pi (0.5 xx10^(-3))(0.2)((sqrt(3))/(2))`
`=4 sqrt(3)pi xx10^(-2)N`
Clearly the force is along -y direction.
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.72|20 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP.No.71|1 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.70|9 Videos
  • CURRENT ELECTRICITY

    RESONANCE ENGLISH|Exercise High Level Problems (HIP)|19 Videos
  • ELECTRO MAGNETIC WAVES

    RESONANCE ENGLISH|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

A coil of inductance 1 H and resistance 10Omega is connected to a resistanceless battery of emf 50 V at time t=0 . Calculate the ratio of rthe rate which magnetic energy is stored in the coil to the rate at which energy is supplied by the battery at t=0.1s .

A coil of self-inductance L is placed in an external magnetic field (no current flows in the coil). The total magnetic flux linked with the coil is phi . The magnetic field energy stored in the coil is

The energy stored in the condenser is

In a series LCR circuit with an ac source of 50 V,R=300 Omega ,frequency v=50/piHz .The average electric field energy, stored in the capacitor and average magnetic energy stored in the coil are 25 mJ and 5 mJ respectively.The RMS current in the circuit is 0.10 A .Then find

Derive an expression for the total magnetic energy stored in two coils with inductances L_(1) and L_(2) and mutual inductance M , when the currents in the coils are I_(1) and I_(2) , respectively.

A 20 Henry inductor coil is connected to a 10ohm resistance in series as shown in figure. The time at which rate of dissipation of energy (Joule's heat) across resistance is equal to the rate at which magnetic energy is stored in the inductor, is:

In the steady state of the circuit shown in the figure the ratio of energy stored in the inductor to th energy stored in the capacitor is 1000000.

In the organism, energy is stored in the form of

A coil having an inductance L and a resistance R is connected to a battery of emf epsilon . Find the time elapsed before, the magnetic field energy stored in the circuit reaches half its maximum value.

A rod mass (M) hinged at (O) is kept in equilibrium with a spring of stiffness (k) as shown in figure. The potential energy stored in the spring is .