The readings of a constant potential difference is noted four times by a student. The student averages these readings but does not take into account the zero error of the voltmeter. The average measurement of the
`|("Reading 1",1.176 V),("Reading 2",1.178 V),("Reading 3",1.177 V),("Reading 4",1.176 V)|`

Options

A. precise and accurate
B. precise but not accurate
C. accurate but not precise
D. not accurate and not precise

Explanation

To solve the problem, we need to calculate the average of the given voltmeter readings and discuss the implications of not accounting for zero error.

### Step 1: List the Readings
The readings taken by the student are:
- Reading 1: 1.176 V
- Reading 2: 1.178 V
- Reading 3: 1.177 V
- Reading 4: 1.176 V

### Step 2: Sum the Readings
We need to sum all the readings:
\[ \text{Total} = 1.176 + 1.178 + 1.177 + 1.176 \]

Calculating the total:
\[ \text{Total} = 1.176 + 1.178 + 1.177 + 1.176 = 4.707 \, \text{V} \]

### Step 3: Calculate the Average
To find the average, we divide the total by the number of readings (which is 4):
\[ \text{Average} = \frac{\text{Total}}{\text{Number of Readings}} = \frac{4.707}{4} \]

Calculating the average:
\[ \text{Average} = 1.17675 \, \text{V} \]

### Step 4: Discuss Zero Error
The problem states that the student did not take into account the zero error of the voltmeter. This means that the average value calculated (1.17675 V) is precise but not accurate. The zero error could shift all readings by a constant value, leading to a systematic error in the average.

### Conclusion
The average measurement of the readings is approximately **1.17675 V**, but it should be noted that this value does not account for any zero error present in the voltmeter.