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Passenger of a train just drops a stone ...

Passenger of a train just drops a stone from it. The train was moving with constant velocity. What is path of the stone as observed by (a) the passenger itself, (b) a man standing on ground?

A

parabola

B

straight line for sometimes & parabola for the remaining time

C

straight line

D

variable path that cannot be defined

Text Solution

Verified by Experts

The correct Answer is:
C
Relative to the person in the train acceleration of the stone is 'g' downward a (acceleration of train) backwards.
According to him : `x=1/2 at^(2), Y=1/2 g t^(2)`
`rArr X/Y=a/grArr Y=g/a xrArr `straight line
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