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Three persons A, B and C are moving along a straight line with constant speed in same direction as shown in figure. Speed of A is 5 m/s and speed of C is 10 m/s. Initially separation between A and B is ‘d’ and between B and C is also d. When ‘B’ catches ‘C’, separation between A and C becomes 3d. Then the speed of B will be:

A

`7.5 m//s`

B

`15 m//s`

C

`20 m//s`

D

`5 m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
B catches C in time t then `t =(d)/(u-10)`
Separation by this time has increased by 'd' between A and C hence
`(10-5) xxd/((u-10))=d`
u=15 m/s
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