Two identical small masses each of mass m are connected by a light inextensible string on a smooth horizontal floor. A constant force F is applied at the mid point of the string as shown in fig. find the acceleration of each mass towards each other.

Options

A. `F/(2m)a/(sqrt(a^(2)-x^(2)))`
B. `F/(2m)x/(sqrt(a^(2)-x^(2)))`
C. `F/(2m) x/a`
D. `F/(2m) (sqrt(a^(2)-x^(2)))/x`

Answer

B

Explanation

`F=2T sin theta`
`a=(T cos theta)/m`
`a=(F cos theta)/(2m sin theta)=F/(2m) x/(sqrt(a^(2)-x^(2)))`