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A person is standing in an elevator. In ...

A person is standing in an elevator. In which situation he finds his weight less than actual when:

A

The elevator moves upward with constant acceleration

B

The elevator moves downward with constant acceleration

C

The elevator moves upwards with uniform velocity

D

The elevetor moves downwards with uniform velocity.

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The correct Answer is:
To determine in which situation a person standing in an elevator feels their weight to be less than their actual weight, we need to analyze the forces acting on the person in different scenarios. ### Step-by-Step Solution: 1. **Understanding Weight**: - The actual weight of a person is given by the formula \( W = mg \), where \( m \) is the mass of the person and \( g \) is the acceleration due to gravity. 2. **Elevator Scenarios**: - We need to consider different scenarios of the elevator's motion: - (a) Elevator moving upward with acceleration - (b) Elevator moving downward with acceleration - (c) Elevator moving upward with uniform velocity - (d) Elevator moving downward with uniform velocity 3. **Case Analysis**: - **(a) Elevator moving upward with acceleration**: - In this case, the effective weight felt by the person is \( W' = mg + ma \) (where \( a \) is the upward acceleration). The person feels heavier. - **(b) Elevator moving downward with acceleration**: - Here, the effective weight felt by the person is \( W' = mg - ma \). If the downward acceleration \( a \) is significant enough, the person will feel lighter than their actual weight. This is the scenario where the person feels their weight is less than actual. - **(c) Elevator moving upward with uniform velocity**: - When the elevator moves with uniform velocity, the acceleration is zero, so the effective weight remains \( W' = mg \). The person feels the same weight as their actual weight. - **(d) Elevator moving downward with uniform velocity**: - Similar to the previous case, the acceleration is zero, and the effective weight remains \( W' = mg \). The person feels the same weight as their actual weight. 4. **Conclusion**: - The only scenario where the person feels their weight is less than their actual weight is when the elevator is moving downward with acceleration. ### Final Answer: The person finds their weight less than actual when the elevator is moving downward with acceleration.

To determine in which situation a person standing in an elevator feels their weight to be less than their actual weight, we need to analyze the forces acting on the person in different scenarios. ### Step-by-Step Solution: 1. **Understanding Weight**: - The actual weight of a person is given by the formula \( W = mg \), where \( m \) is the mass of the person and \( g \) is the acceleration due to gravity. 2. **Elevator Scenarios**: ...
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RESONANCE ENGLISH-NEWTONS LAWS OF MOTION AND FRICTION-Exercise
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