A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of `5 m//s^(2)`. And when the horizontal force is doubled, it gets an acceleration of `18 m//s^(2)`. The coefficient of friction between the body and the horizontal surface is

Options

A. 0.2
B. 0.4
C. 0.6
D. 0.8

Explanation

To solve the problem, we will analyze the forces acting on the body and use Newton's second law of motion. Let's break down the solution step by step.

### Step 1: Identify the forces acting on the body
The forces acting on the body are:
- The applied force \( F \) (in the horizontal direction)
- The frictional force \( f \) (opposing the motion)
- The weight of the body \( mg \) (acting downwards)
- The normal force \( N \) (acting upwards)
...