Power supplied to a mass `2 kg` varies with time as `P = (3t^(2))/(2)` watt. Here `t` is in second . If velocity of particle at `t = 0 is v = 0`, the velocity of particle at time `t = 2s` will be:

Options

A. 1 m/s
B. 4m/s
C. 2m/s
D. `sqrt(2) m//s`

Answer

C

Explanation

Applying work energy theorem
`K_(f)=K_(i)`+work done
`1/2 mv^(2)=0+int_(0)^(2) Pdt=int_(0)^(2)(3t^(2))/2 dt`
Solving we get v=2m/s.