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A spring of force constant 800 Nm^(-1) h...

A spring of force constant 800 `Nm^(-1)` has an extension of 5 cm. The work done in extending it from 5 cm to 15 cn is

A

16J

B

8J

C

32J

D

24 J

Text Solution

Verified by Experts

The correct Answer is:
B

`W_(C)=-DeltaU`
`=(U_("final")-U_("initial"))`
`=-(1/2xxkxx15^(2)-1/2xxkxx5^(2))` ltBrgt `W_(c)=8` joule
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