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A stone of mass m tied to a string of le...

A stone of mass m tied to a string of length l is rotated in a circle with the other end of the string as the centre. The speed of the stone is v. If the string breaks, the stone will move

A

`(mv^(2))/r+mg`

B

`(mv^(2))/r-mg`

C

`(mv^(2))/r`

D

`mg`

Text Solution

Verified by Experts

The correct Answer is:
A
`T-mg=(mv^(2))/r` (centripetal force at lowest point)
`T=(mv^(2))/r+mg`
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