For a body in circular motion with a constant angular velocity, the magnitude of the average acceleration over a period of half a revolution is..... times the magnitude of its instantaneous acceleration

Options

A. `1/pi`
B. `2/pi`
C. `5/pi`
D. `3/pi`

Answer

B

Explanation

ltagt =average acceleration
`=(Deltav)/(Deltat)=(2 omegaR)/(piR//omegaR)`
`=(2R omega^(2))/(pi)`
Instantaneous acceleration =`omega^(2)R`
`( lt a gt)/a=2/(pi)`