A car moves at a constant speed on a road as shown in figure. The normal force by the road on the car is `N_A and N_B` when it is at the points A and B respectively
.

Options

A. `N_(A)=N_(B)`
B. `N_(A)gtN_(B)`
C. `N_(A)ltN_(B)`
D. `N_(C)=N_(A)`

Answer

B

Explanation

for normal reaction at points A and B
`mg-N=(mv^(2))/r`
`N=mg=(mv^(2))/r`
`rArr N_(A) gt N_(B)` and normal reaction at C is `N_(O)`=mg , so `N_(C) gt N_(A) gt N_(B)`