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The block of mass M moving on the frict...

The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision is

A

`sqrt(mk)L`

B

`(kL^(2))/(2M)`

C

zero

D

`(ML^(2))/k`

Text Solution

Verified by Experts

The correct Answer is:
A
According to conservation of energy
`1/2 kL^(2)=1/2 M upsilon^(2)`
`rArr kL=((M upsilon)^(2))/M`
`MkL^(2)=p^(2)` `(p=m upsilon)`
`:. P=Lsqrt(MK)`
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