A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings `T_1/T_2` is:

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `4:3`

Answer

C

Explanation

By equation forces in vertical direction
`T_(1)+T_(2)=mg`
`T_("c.o.m")=0`
`T_(1)L/4-T_(2)L/2=0`
`T_(1)=2T_(2)`
The ratio of `T_(1)//T_(2)` is `2:1`