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A string is stretched by a force of 40 n...

A string is stretched by a force of 40 newton. The mass of 10 m length of this string is 0.01 kg. the speed of transverse waves in this string will be

A

400m/s

B

40 m/s

C

200 m/s

D

80 m/s

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The correct Answer is:
To find the speed of transverse waves in a string, we can use the formula: \[ V = \sqrt{\frac{T}{\mu}} \] where: - \( V \) is the speed of the wave, - \( T \) is the tension in the string (in Newtons), - \( \mu \) is the mass per unit length of the string (in kg/m). **Step 1: Calculate the mass per unit length (\( \mu \))** Given: - The mass of the string = 0.01 kg - The length of the string = 10 m We can calculate \( \mu \) using the formula: \[ \mu = \frac{\text{mass}}{\text{length}} \] Substituting the values: \[ \mu = \frac{0.01 \, \text{kg}}{10 \, \text{m}} = 0.001 \, \text{kg/m} \] **Step 2: Substitute the values into the wave speed formula** We know: - Tension \( T = 40 \, \text{N} \) - Mass per unit length \( \mu = 0.001 \, \text{kg/m} \) Now substitute these values into the wave speed formula: \[ V = \sqrt{\frac{T}{\mu}} = \sqrt{\frac{40 \, \text{N}}{0.001 \, \text{kg/m}}} \] **Step 3: Simplify the expression** Calculating the fraction: \[ \frac{40 \, \text{N}}{0.001 \, \text{kg/m}} = 40000 \, \text{m}^2/\text{s}^2 \] Now take the square root: \[ V = \sqrt{40000 \, \text{m}^2/\text{s}^2} = 200 \, \text{m/s} \] **Final Answer:** The speed of transverse waves in the string is \( 200 \, \text{m/s} \). ---

To find the speed of transverse waves in a string, we can use the formula: \[ V = \sqrt{\frac{T}{\mu}} \] where: - \( V \) is the speed of the wave, - \( T \) is the tension in the string (in Newtons), - \( \mu \) is the mass per unit length of the string (in kg/m). ...
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