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A police car horn emits a sound at a fre...

A police car horn emits a sound at a frequency 240 Hz. When the car is at rest. If the speed of the sound is 330 m/s the frequency heard by an observer who is approching the car at a speed of 11 m/s is

A

248 Hz

B

244Hz

C

240 Hz

D

230 Hz

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The correct Answer is:
To solve the problem of finding the frequency heard by an observer approaching a police car emitting a sound at a frequency of 240 Hz, we can use the Doppler effect formula for sound. Here’s the step-by-step solution: ### Step 1: Identify the given values - Frequency of the source (police car horn), \( f_0 = 240 \, \text{Hz} \) - Speed of sound in air, \( v = 330 \, \text{m/s} \) - Speed of the observer (approaching the source), \( v_o = 11 \, \text{m/s} \) - Speed of the source (police car), \( v_s = 0 \, \text{m/s} \) (since the car is at rest) ### Step 2: Write the Doppler effect formula The formula for the observed frequency \( f \) when the source is stationary and the observer is moving towards the source is given by: \[ f = f_0 \left( \frac{v + v_o}{v - v_s} \right) \] Where: - \( f \) is the frequency heard by the observer. - \( f_0 \) is the emitted frequency of the source. - \( v \) is the speed of sound. - \( v_o \) is the speed of the observer towards the source. - \( v_s \) is the speed of the source (which is zero in this case). ### Step 3: Substitute the values into the formula Substituting the known values into the formula: \[ f = 240 \left( \frac{330 + 11}{330 - 0} \right) \] ### Step 4: Simplify the equation Calculating the numerator and denominator: \[ f = 240 \left( \frac{341}{330} \right) \] ### Step 5: Calculate the observed frequency Now, perform the multiplication: \[ f = 240 \times \frac{341}{330} \] Calculating this gives: \[ f = 240 \times 1.034 \] \[ f \approx 248.16 \, \text{Hz} \] ### Step 6: Round to the nearest whole number Since frequency is typically expressed in whole numbers, we round it: \[ f \approx 248 \, \text{Hz} \] ### Conclusion The frequency heard by the observer who is approaching the police car is approximately **248 Hz**. ---

To solve the problem of finding the frequency heard by an observer approaching a police car emitting a sound at a frequency of 240 Hz, we can use the Doppler effect formula for sound. Here’s the step-by-step solution: ### Step 1: Identify the given values - Frequency of the source (police car horn), \( f_0 = 240 \, \text{Hz} \) - Speed of sound in air, \( v = 330 \, \text{m/s} \) - Speed of the observer (approaching the source), \( v_o = 11 \, \text{m/s} \) - Speed of the source (police car), \( v_s = 0 \, \text{m/s} \) (since the car is at rest) ...
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RESONANCE ENGLISH-SOUND WAVES-Exercise- 3 PART - I
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  14. A police car with a siren of frequency 8 kHz is moving with uniform ve...

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  16. A student is performing the experiment of resonance column. The diamet...

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  17. Two vehicles, each moving with speed u on the same horizontal straight...

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