A prism of refractive index `mu_g` deviates the incident ray towards its base. If it is immersed in a transparent liquid of refractive index `mu_1` such that `mu_1 gt mu_g` then prism would

Options

A. deviate the ray towards its base
B. deviate the ray away from its base
C. not deviate the ray at all
D. nothing can be said

Explanation

To solve the problem, we need to analyze the behavior of light as it passes through a prism when it is immersed in a liquid with a higher refractive index than that of the prism itself. Here's a step-by-step solution:

### Step 1: Understand the Prism's Behavior in Air
- A prism with a refractive index \( \mu_g \) deviates the incident ray towards its base when it is in air (where the refractive index is \( \mu_a \)).
- This occurs because the refractive index of the prism is greater than that of air (\( \mu_g > \mu_a \)), causing the light ray to bend towards the normal when entering the prism.

### Step 2: Analyze the Situation When Immersed in a Liquid
- Now, consider the prism immersed in a transparent liquid with a refractive index \( \mu_1 \) such that \( \mu_1 > \mu_g \).
- Since \( \mu_1 \) is greater than \( \mu_g \), this means that the liquid is denser than the glass of the prism.

### Step 3: Determine the Ray's Path in the Liquid
- When the incident ray strikes the surface of the prism from the liquid, it will now bend away from the normal because it is moving from a denser medium (liquid) to a rarer medium (glass).
- This bending away from the normal will cause the ray to deviate away from the base of the prism.

### Step 4: Conclusion
- Therefore, when the prism is immersed in a liquid with a refractive index greater than that of the prism, it will deviate the ray away from its base.

### Final Answer
The prism would deviate the ray away from its base.

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