If the electric flux entering and leaving an enclosed surface respectively, is `phi_(1)` and `phi_(2)`, then the electric charge inside the surface will be

Options

A. `(phi_(2)-phi_(1)) epsilon_(0)`
B. `(phi_(1)+phi_(2))//epsilon_(0)`
C. `(phi_(2)-phi_(1))//epsilon_(0)`
D. `(phi_(1)+phi_(2))epsilon_(0)`

Answer

A

Explanation

`phi=(q_(ln))/(epsilon_(0))`
Net `phi=phi_(2)-phi_(1)`
`:. q_("in")=(phi_(2)-phi_(1)) epsilon_(0)`