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Two small balls having equal positive charge Q (coulumb) on each suspended by two insulating strings of equal length L (metre) from a hook fixed to a stand. The whole set-up is taken in a satellite into space where there is no gravity (state of weightlessness). Then tension (newtons) in each string is:

A

`(Q^(2))/(4piin_(0)L^(2))`

B

`(Q^(2))/(8piin_(0) L^(2))`

C

`(Q^(2))/(12 pi in_(0)L^(2))`

D

`(Q^(2))/(16 pi in_(0)L^(2))`

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The correct Answer is:
To solve the problem, we will analyze the forces acting on the two charged balls when they are in a state of weightlessness in space. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two small balls, each with an equal positive charge \( Q \), suspended by insulating strings of equal length \( L \). - The system is taken into space where there is no gravity (weightlessness). 2. **Identifying Forces**: - In a gravitational field, the weight of each ball would exert a downward force \( mg \) (where \( m \) is the mass of the ball and \( g \) is the acceleration due to gravity). - However, in the absence of gravity, the weight \( mg = 0 \). 3. **Electrostatic Force**: - The only force acting on the balls is the electrostatic force due to their charges. - Since both balls have the same charge \( Q \), they will repel each other with a force given by Coulomb's Law: \[ F = \frac{k \cdot Q^2}{r^2} \] - Here, \( k \) is Coulomb's constant, \( r \) is the distance between the two charges. 4. **Distance Between Charges**: - When the balls repel each other to the maximum extent, the distance \( r \) between them will be \( 2L \) (since each string has length \( L \)). 5. **Calculating the Electrostatic Force**: - Substituting \( r = 2L \) into the formula for electrostatic force: \[ F = \frac{k \cdot Q^2}{(2L)^2} = \frac{k \cdot Q^2}{4L^2} \] 6. **Tension in the Strings**: - In the state of weightlessness, the tension \( T \) in each string will equal the electrostatic force acting between the two charges: \[ T = \frac{k \cdot Q^2}{4L^2} \] 7. **Substituting the Value of \( k \)**: - The value of \( k \) is given by: \[ k = \frac{1}{4\pi \epsilon_0} \] - Therefore, substituting this into the equation for tension: \[ T = \frac{1}{4\pi \epsilon_0} \cdot \frac{Q^2}{4L^2} \] - Simplifying this gives: \[ T = \frac{Q^2}{16\pi \epsilon_0 L^2} \] 8. **Final Result**: - The tension in each string is: \[ T = \frac{Q^2}{16\pi \epsilon_0 L^2} \]

To solve the problem, we will analyze the forces acting on the two charged balls when they are in a state of weightlessness in space. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two small balls, each with an equal positive charge \( Q \), suspended by insulating strings of equal length \( L \). - The system is taken into space where there is no gravity (weightlessness). ...
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