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In the above question, the surface charg...

In the above question, the surface charge densities have the correct relation is-

A. `sigma_(A) gt sigma_(B) gt sigma_(C) gt sigma_(D)`
B. `sigma_(A)=sigma_(B)=sigma_(C)=sigma_(D)`
C. `sigma_(D) gt sigma_(C) gt sigma_(B) gt sigma_(A)`
D. `sigma_(C) lt sigma_(B) gt sigma_(A) gt sigma_(D)`

A

`sigma_(A) gt sigma_(B) gt sigma_(C) gt sigma_(D)`

B

`sigma_(A)=sigma_(B)=sigma_(C)=sigma_(D)`

C

`sigma_(D) gt sigma_(C) gt sigma_(B) gt sigma_(A)`

D

`sigma_(C) lt sigma_(B) gt sigma_(A) gt sigma_(D)`

Text Solution

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The correct Answer is:
To solve the problem regarding the surface charge densities on different parts of a conductor, we will analyze the relationship based on the geometry of the surfaces involved. ### Step-by-Step Solution: 1. **Identify the Surfaces**: We have four surfaces on the conductor: - Surface A: Pointed end - Surface B: Small semicircle - Surface C: Long semicircle - Surface D: Flat surface 2. **Understand the Geometry**: - The radius of curvature for each surface is different: - Surface A (pointed) has the smallest radius of curvature. - Surface B (small semicircle) has a larger radius than A but smaller than C. - Surface C (long semicircle) has a larger radius than B. - Surface D (flat surface) has an infinite radius of curvature. 3. **Apply the Concept of Charge Density**: - The surface charge density (σ) is inversely proportional to the radius of curvature (R). This means: \[ \sigma \propto \frac{1}{R} \] - Therefore, the smaller the radius of curvature, the higher the surface charge density. 4. **Establish the Relationships**: - Since Surface A has the smallest radius, it will have the highest charge density: \[ \sigma_A > \sigma_B > \sigma_C > \sigma_D \] - This implies: - \(\sigma_A\) (pointed end) > \(\sigma_B\) (small semicircle) > \(\sigma_C\) (long semicircle) > \(\sigma_D\) (flat surface). 5. **Select the Correct Option**: - Based on the relationships derived, we can conclude that the correct option is: - **A.** \(\sigma_A > \sigma_B > \sigma_C > \sigma_D\) ### Final Answer: The correct relation of the surface charge densities is: **A.** \(\sigma_A > \sigma_B > \sigma_C > \sigma_D\)
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