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STATEMENT 1: When a negative charge -q i...

STATEMENT 1: When a negative charge -q is released at a distance R from the centre and along the axis of a uniformly and positvely charged fixed ring of radius R, the negative charge does oscillation but not SHM. STATEMENT 2: The force on negative charge is always towards the centre of the ring but it is not proportional to the displacement from the centre of the ring.

A

Statement-1 is true, Statement-2: is true, Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is true, Statement-2: is true, Statement-2 is NOT a correct explanation for Statement-1.

C

Statement-1 is true but statement-2 is false

D

Statement-1 is false, Statement-2 is true

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The correct Answer is:
To solve the given problem, we need to analyze the two statements provided regarding the behavior of a negative charge released near a uniformly positively charged ring. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a uniformly positively charged ring with radius \( R \). - A negative charge \( -q \) is placed at a distance \( R \) along the axis of the ring from its center. 2. **Force on the Negative Charge**: - The force acting on the negative charge due to the positive charge on the ring can be calculated using Coulomb's law. - The force \( F \) on the charge \( -q \) at distance \( R \) from the center of the ring is given by: \[ F = \frac{k \cdot Q \cdot (-q)}{R^2} \] - Here, \( k \) is Coulomb's constant, and \( Q \) is the total charge of the ring. 3. **Direction of the Force**: - The force is attractive, meaning it acts towards the center of the ring. Thus, the negative charge experiences a force directed towards the center. 4. **Oscillation of the Charge**: - When the charge \( -q \) is released, it will move towards the center of the ring due to the attractive force. - Upon reaching the center, it will continue moving due to inertia and will cross the center, moving to a distance \( R \) on the opposite side. - The charge will then be pulled back towards the center again, leading to oscillatory motion. 5. **Nature of the Oscillation**: - The oscillation is not simple harmonic motion (SHM) because, in SHM, the restoring force must be directly proportional to the displacement from the equilibrium position. - In this case, the force is not proportional to the displacement from the center of the ring; instead, it varies with the square of the distance. 6. **Conclusion on Statements**: - **Statement 1**: True - The negative charge does oscillate but not in SHM. - **Statement 2**: True - The force is directed towards the center but is not proportional to the displacement. ### Final Answer: Both statements are true, and statement 2 correctly explains statement 1.
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RESONANCE ENGLISH-ELECTROSTATICS-Exercise
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  5. A large nonconducting sheet M is given a uniform charge density. Two u...

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