Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.

Options

A. `sqrt((GM)/R)`
B. `sqrt((GM)/(2R))`
C. `sqrt((GM)/(4R))`
D. `sqrt((2GM)/R)`

Answer

C

Explanation

`(GM)/((2R)^(2))M=(MV^(2))/RrArr V=sqrt((GM)/(4R))`