A satellite of mass `m` revolves around the earth of radius `R` at a height x from its surface. It g is the acceleration due to gravity on the surface of the earth, the orbit speed of the satellite is

Options

A. gx
B. `(gR)/(R-x)`
C. `(gR^(2))/(R+x)`
D. `((gR^(2))/(R+x))^(1//2)`

Answer

D

Explanation

`(mv^(2))/(R+X)=(GM)/((R+X)^(2))=(gR^(2))/((R+X)^(2))` or `V=[(gR^(2))/(R+X)]^(1//2)`