If on applying the potential of 20V on a conductor its conductance becomes `8(Omega)^(-1)`, then the current flowing through it will be:

Options

A. 120A
B. 160A
C. 90A
D. 80A

Explanation

To find the current flowing through a conductor when a potential of 20V is applied and its conductance is given as \(8 \, \Omega^{-1}\), we can follow these steps:

### Step 1: Understand the relationship between conductance and resistance.
Conductance (G) is the reciprocal of resistance (R). Therefore, we can express this relationship as:
\[ G = \frac{1}{R} \]
Given that the conductance \(G = 8 \, \Omega^{-1}\), we can find the resistance \(R\) as follows:
\[ R = \frac{1}{G} = \frac{1}{8} \, \Omega \]

### Step 2: Use Ohm's Law to find the current.
Ohm's Law states that:
\[ V = I \cdot R \]
Where:
- \(V\) is the voltage (20V in this case),
- \(I\) is the current we want to find,
- \(R\) is the resistance we calculated in Step 1.

Substituting the known values into Ohm's Law:
\[ 20V = I \cdot \left(\frac{1}{8} \, \Omega\right) \]

### Step 3: Solve for the current \(I\).
Rearranging the equation to solve for \(I\):
\[ I = \frac{V}{R} = \frac{20V}{\frac{1}{8} \, \Omega} \]
This simplifies to:
\[ I = 20V \cdot 8 = 160A \]

### Conclusion:
The current flowing through the conductor is \(160A\).

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