The potential difference between points `A` and `B` is

Options

A. `(20)/(7)V`
B. `(40)/(7)V`
C. `(10)/(7)V`
D. zero

Answer

D

Explanation

From the given figure, current through lower branch of resistance which are joined in series is `i_(1)=10/(4+3) =10/7 A`
Again current through upper branch of resistance which are, also connected in series, is
`i_(2)=10/(8+6) =10/14 A`
Now, according to the Krichhoff's voltage law
`V_(E)-V_(A)=8xxi_(2)-4xxi_(1)=8xx10/14-4xx10/7 =0`