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A cylindrical rod having temperature T1 ...

A cylindrical rod having temperature `T_1` and `T_2` at its end. The rate of flow of heat `Q_1` cal/sec. If all the linear dimension are doubled keeping temperature remain const. then rate of flow of heat `Q_2` will be : -

A

`4 Q_(1)`

B

`2Q_(1)`

C

`(Q_(1))/4`

D

`(Q_(1))/2`

Text Solution

Verified by Experts

The correct Answer is:
B
`Q_(1)=(DeltaT)/((l/(k pir^(2)))), Q_(2)=(DeltaT)/((2l)/(kpi(2r)^(2)))rArr (Q_(2))/(Q_(1))=2`
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