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Consider a composite slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is

A

`sqrt(2)`

B

3k

C

`(4)/(3) k`

D

`(2)/(3) k`

Text Solution

Verified by Experts

The correct Answer is:
C

Equivalent thermal circuit
`1/(R_(eq))=1/(R_(1))+1/(R_(2))rArr (K_(eq)xx2A)/l=(KA)/l+(2KA)/lrArr K_(eq) =3/2 K`
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