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A capacitor is conneted to a cell emf E ...

A capacitor is conneted to a cell emf `E` having some internal resistance `r`. The potential difference across the

A

cell is `lt E`

B

cell is E

C

capacitor is gtE

D

capacitor is `lt E`

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The correct Answer is:
To solve the problem of finding the potential difference across a capacitor connected to a cell with internal resistance, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Circuit Configuration**: - We have a capacitor with capacitance \( C \) connected to a cell with an electromotive force (emf) \( E \) and an internal resistance \( r \). - The circuit can be visualized as a capacitor in series with the internal resistance of the cell. 2. **Identify the Steady State Condition**: - When the capacitor is fully charged, it reaches a steady state. In this condition, the current flowing through the circuit becomes zero. - This is because a fully charged capacitor acts like an open circuit, meaning no current can flow through it. 3. **Apply Kirchhoff’s Voltage Law**: - According to Kirchhoff’s Voltage Law, the sum of the potential differences in a closed loop must equal zero. - In our case, the potential difference across the cell (emf \( E \)) must equal the potential difference across the capacitor plus the potential drop across the internal resistance \( r \). 4. **Current in Steady State**: - Since the current \( I \) in the circuit is zero when the capacitor is fully charged, we can express this as: \[ I = 0 \] - Therefore, the voltage drop across the internal resistance \( r \) is: \[ V_r = I \cdot r = 0 \cdot r = 0 \] 5. **Determine the Potential Difference Across the Capacitor**: - Since the current is zero, the entire emf \( E \) is applied across the capacitor. Thus, the potential difference across the capacitor \( V_C \) is: \[ V_C = E - V_r = E - 0 = E \] 6. **Conclusion**: - The potential difference across the capacitor, when it is fully charged, is equal to the emf of the cell, which is \( E \). ### Final Answer: The potential difference across the cell is \( E \).

To solve the problem of finding the potential difference across a capacitor connected to a cell with internal resistance, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Circuit Configuration**: - We have a capacitor with capacitance \( C \) connected to a cell with an electromotive force (emf) \( E \) and an internal resistance \( r \). - The circuit can be visualized as a capacitor in series with the internal resistance of the cell. ...
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