A 4muF capacitor is charged to 400V and ...

A `4muF` capacitor is charged to `400V` and then its plates are joined through a resistance of `1 k Omega`. The heat produced in the resistance is

0.16J

0.32J

0.64J

1.28J

Text Solution

Verified by Experts

The correct Answer is:

Heat produced in the resistor =energy strored in capacitor
`=1/2 CV^(2)=1/2 4xx10^(-6) xx(400)^(2)=0.32 J`

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