In the circuit shown in figure C(1) = 2 ...

In the circuit shown in figure `C_(1) = 2 C_(2)`. Capacitance `C_(1)` is charged to a potential of V. The current in the circuit just after the switch S is closed is

`(2V)/R`

Infinite

`V/(2R)`

Text Solution

Verified by Experts

The correct Answer is:

at t=0
`i=V/(2R)`

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