If the two plates of the charged capacitor are connected by a wire, then

Options

A. potential will becomes infinte
B. charge will becomes infinite
C. capacitor will get discharged
D. charge will becomes double that of earlier one

Explanation

To solve the question of what happens when the two plates of a charged capacitor are connected by a wire, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Initial Condition**:
- A capacitor is initially charged to a voltage \( V \). This means it has a certain amount of charge \( Q \) stored on its plates, which is related by the formula \( Q = C \times V \), where \( C \) is the capacitance of the capacitor.

2. **Connecting the Plates with a Wire**:
- When the two plates of the charged capacitor are connected by a wire, it creates a path for charge to flow between the plates. This effectively short-circuits the capacitor.

3. **Effect on Potential Difference**:
- In a short-circuit condition, the potential difference across the capacitor becomes \( 0 \) volts. This is because the wire allows charges to move freely, neutralizing the voltage difference.

4. **Effect on Charge**:
- Since the potential difference \( V \) is now \( 0 \), we can analyze the charge using the formula \( Q = C \times V \). As \( V \) approaches \( 0 \), the charge \( Q \) also approaches \( 0 \) because \( C \) is a constant. Therefore, the capacitor discharges its stored charge.

5. **Conclusion**:
- The capacitor gets discharged when the plates are connected by a wire. The charge on the capacitor decreases to \( 0 \) as the potential difference drops to \( 0 \).

### Final Answer:
The correct conclusion is that when the two plates of a charged capacitor are connected by a wire, the capacitor will get discharged.

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