Two identical capacitors 1 and 2 are connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of constant K. `Q_(1)` and `Q_(2)` are the charges stored in 1 and 2. Now, the dielectric slab, is removed and the corresponding charges are `Q'_(1)` and `Q'_(2)`. Then

Options

A. `(Q'_(1))/(Q_(1))=(k+1)/k`
B. `(Q'_(2))/(Q_(2))=(k+1)/2`
C. `(Q'_(2))/(Q_(2))=(k+1)/(2k)`
D. `(Q'_(1))/(Q_(1))=k/2`

Answer

C

Explanation

`Q_(2)=Q_(1)=(KC)/(K+1) ErArr Q_(2)^(2)=Q_(1)^(2)=C/2E rArr (Q_(2)^(1))/(Q_(2))=(K+1)/(2K)`