A charged particle (charge q) is moving in a circle of radius R with uniform speed v.
The associated magnetic momment `mu` is given by

Options

A. `(qvR)/2`
B. `qvR^(2)`
C. `(qvR^(2))/2`
D. qvR

Answer

A

Explanation

As revolving charge is equivalent to a current, so,
`i=qf=qxx(omega)/(2pi)`
But `omega=V/R`
Where R is radius of circle and v is uniform speed of charged particle.
Therefore, `i=(qv)/(2piR)`
Now, magnetic moment associated with charged particle is given by
`mu=IA=IxxpiR^(2)`
`mu=(qv)/(2piR)xxpiR^(2)=1/2 qvR`