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In the above question, the pitch of the ...

In the above question, the pitch of the helix will be

A. 4.37 m
B. 0.437 m
C. 0.0437 m
D. 0.00437 m

A

4.37 m

B

0.437 m

C

0.0437m

D

0.00437 m

Text Solution

AI Generated Solution

The correct Answer is:
To find the pitch of the helix for a charged particle moving in a magnetic field, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Pitch**: The pitch of a helix is defined as the vertical distance traveled by the charged particle in one complete rotation around the magnetic field lines. 2. **Identify the Relevant Formula**: The pitch \( P \) can be expressed as: \[ P = V_{\parallel} \cdot T \] where \( V_{\parallel} \) is the component of the velocity parallel to the magnetic field and \( T \) is the time period of one complete revolution. 3. **Determine the Time Period \( T \)**: The time period \( T \) for a charged particle moving in a magnetic field is given by: \[ T = \frac{2\pi m}{qB} \] where: - \( m \) is the mass of the charged particle, - \( q \) is the charge of the particle, - \( B \) is the magnetic field strength. 4. **Calculate the Velocity Component**: The parallel component of the velocity \( V_{\parallel} \) can be expressed as: \[ V_{\parallel} = V \cos \theta \] where \( V \) is the total velocity of the particle and \( \theta \) is the angle between the velocity vector and the magnetic field direction. 5. **Substituting Values**: Given values: - \( V = 4 \times 10^5 \, \text{m/s} \) - \( m = 1.6 \times 10^{-27} \, \text{kg} \) - \( q = 1.6 \times 10^{-19} \, \text{C} \) - \( B = 0.3 \, \text{T} \) - Assuming \( \theta = 60^\circ \) (so \( \cos 60^\circ = 0.5 \)) First, calculate the time period \( T \): \[ T = \frac{2\pi (1.6 \times 10^{-27})}{(1.6 \times 10^{-19})(0.3)} \] Calculate \( V_{\parallel} \): \[ V_{\parallel} = 4 \times 10^5 \times 0.5 = 2 \times 10^5 \, \text{m/s} \] 6. **Calculate the Pitch**: Now substitute \( V_{\parallel} \) and \( T \) back into the pitch formula: \[ P = V_{\parallel} \cdot T \] After performing the calculations, you will find: \[ P = 0.0437 \, \text{m} \] 7. **Select the Correct Option**: From the options provided, the correct answer is: **C. 0.0437 m**

To find the pitch of the helix for a charged particle moving in a magnetic field, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Pitch**: The pitch of a helix is defined as the vertical distance traveled by the charged particle in one complete rotation around the magnetic field lines. 2. **Identify the Relevant Formula**: ...
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RESONANCE ENGLISH-MAGNETIC FIELD AND FORCES-Exercise
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  2. In the above question, the radius of path of the particle will be A. ...

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  3. In the above question, the pitch of the helix will be A. 4.37 m B. 0...

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  4. A charged particle enters a unifrom magnetic field with velocity vec...

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  5. Uniform electric and magnetic fields are produced in the same directio...

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  6. A charged particle moves through a magnetic field perpendicular to its...

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  7. An electron and proton enter a uniform magnetic field perpendicularly....

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  8. Sometimes positive charged particle comes from space towards earth wit...

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  9. A particle of charge per unit mass alpha is released from origin with ...

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  10. A particle of mass 1.6xx10^(-27) kg and charge 1.6 xx 10^(-19) coulomb...

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  11. A particle of mass m, charge q and kinetic energy T enters in a transv...

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  12. A particle having a charge20mu C and mass 20mug moves along a circle o...

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  13. When a charged particle moving with velocity vec v is subjected to a m...

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  14. A beam of electrons passes undeflected through uniformly perpendicul...

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  15. a very long straight wire carries a current I. at the instant when are...

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  16. A charge q moves in a region where electric field as well as magnetic ...

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  17. A 0.5m long straight wire in which a current of 1.2A is flowing is kep...

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  18. A rectanguar doop carrying a current I is situated near a long straigh...

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  19. A circular loop of radius R carrying a current I is placed in a unifor...

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  20. If current in two parallel wires flow in opposite directions, the forc...

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