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In the circuit shown, the AC source has ...

In the circuit shown, the AC source has voltage V = 20cos(`omega`t)volt with `omega` = 200 `rads^(-1)` the amplitude of the current will be nearest to

A

2A

B

3.3A

C

`2//sqrt(5)A`

D

`sqrt(5)A`

Text Solution

Verified by Experts

The correct Answer is:
A
`X_(L)=L omega=10 `
`X_(C)=1/(C omega)=10 `
`X_(L)-X_(C)=0`
So, Z=R=6+4 =10
`I_(0)=V_(0)//Z =2A`
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