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A coil of 200 Omega resistance and 1.0...

A coil of 200 `Omega` resistance and `1.0` H inductance is connected to an ac source of frequency `200//2pi` Hz .Phase angle between potential and current will be :

A

`30^(@)`

B

`90^(@)`

C

`45^(@)`

D

`0^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
`tan phi=(x_(L))/R=(L omega)/R=1`
`phi=45^(@)`
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