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The photoelectric work function for a me...

The photoelectric work function for a metal surface is `4.125eV`. The cut-off wavelength for this surface is

A

200 nm

B

300 nm

C

150 nm

D

420 nm

Text Solution

Verified by Experts

The correct Answer is:
B
`phi=(hc)/(lambda_(th)) rArr lambda_(th)=(hc)/(phi) =300 nm`
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