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In a common-base of mode of transistor, ...

In a common-base of mode of transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor (2) will be:

A

49

B

50

C

51

D

48

Text Solution

Verified by Experts

The correct Answer is:
A
`beta=(I_(C))/(I_(B)) ` and `I_(E)=I_(C)+I_(B)`
`:. beta=(I_(C))/(I_(E)-I_(C))=5.488/(5.60-5.488) =49`
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