Distance between a frog and an insect on a horizontal plane is 10m. Frog can jump with a maximum speed of `sqrt(10) m//s. g=10 m//s^(2)`. Minimum number of jumps required by the frog to catch the insect is

Options

A. 5
B. 10
C. 100
D. 50

Answer

B

Explanation

For minimum number of jumps, range must be maximum.
maximum range `=(u^(2))/g =((sqrt(10))^(2))/10=1` meter.
Total distance to be covered =10 meter
So total step =10