Four thin rods of same mass M and same length 1, form a square as shown in figure. Find moment of inertia of this system about an axis through centre 0 and perpendicular to its plane?

Options

A. `10/3Ml^(2)`
B. `(Ml^(2))/3`
C. `(Ml^(2))/6`
D. `2/3 Ml^(2)`

Answer

A

Explanation

`rArr I=(Ml^(2))/3+(Ml^(2))/3+2[(Ml^(2))/12+M((sqrt(5)l)/2)^(2)]=(10 Ml^(2))/3`