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A force of 6.4 N stretches a vertical sp...

A force of 6.4 N stretches a vertical spring by 0.1 m. The mass (in kg) that must be suspended from the spring so that it oscillates with a time period of `(pi)/(4)` second.

A

`(pi)/4 kg`

B

`4/(pi) kg`

C

`1 kg`

D

10 kg

Text Solution

Verified by Experts

The correct Answer is:
C
Spring constant `K= (6.4)/(0.1) =64 N//m`
Now `T=2pisqrt(m/k)` or `pi/4 =2pisqrt(m/64) :. M=1 kg `
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