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The electric field intensity at all poin...

The electric field intensity at all points in space is given by `vecE = sqrt(3)hati - hatj` `V//m`. The nature of equipotential lines is x-y plane is given by

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B

C

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The correct Answer is:
C
The direction of uniform electric field E in x-y plane is as shown in figure.

The equipotential lines will be perpendicular to electric field. Also electric field points from hight potential region towards low potential region. therefore natures of equipotential lines in x-y plane is given by figure 2.
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The electric field intensity at all points in space is given by vec(E) = sqrt(3) hat (i) - hat (j) volts/metre. A square frame LMNO of side 1 metre is shown in figure. The point N lies in x-y plane. The initial angle between line ON and x-axis is theta = 60^(@) The work done by electric field in taking a point charge of 1 muC from origin O to point M is -

The electric field intensity at all points in space is given by vec(E) = sqrt(3) hat (i) - hat (j) volts/metre. A square frame LMNO of side 1 metre is shown in figure. The point N lies in x-y plane. The initial angle between line ON and x-axis is theta = 60^(@) The magnitude of electric flux through area enclosed in square frame LMNO is -

the electric field intensity at all points is space is given by vecE=sqrt3hati-hatj volts/meter. A square frame LMNO of side 1 meter is shown in the figure. The point N lies in x-y plane. The initial angle between line ON and x -axis is theta = 60^(@) The work done by electric field in taking a point charge 1muC from origin O to point M is

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