In the given circuit, in steady state we may say: (capacitor are initially uncharged)

Options

A. potential drop across the capacitor `C_(1)` is 4v
B. potential drops across `10 Omega` resistance 10 V
C. charge on `C_(1)` and `C_(2)` is `20 muC`
D. ratio of charge on `C_(1)` and `C_(2)` is 10 :4

Answer

A

Explanation

`C_(eq)=(10xx4)/(10+4)=40/14`
`Q=C_(eq) V=40/14xx14 =40 mu C`
`V_(c_(1))=40/10 =4v`
`V_(c_(2))=40/4=10 v.`