Find the binding energy of `._26^56 Fe`. Atomic mass of `.^56 Fe` is `55.9349 u` and that of `.^1 H` is `1.00783 u`. Mass of neutron `= 1.00867 u`.

Explanation

The number of protons in `._(26)^(58)(Fe) = 26` and the number of neutrons `= 56-26 = 30`
The binding energ of `._(26)^(56)(Fe)` is
`=[26 xx 1.00783 u + 30 xx 1.00867 u - 55.9349 u]c^(2)`
`= (0.52878 u)c^(2)`
`= (0.52878 u) (931 Me V//u) = 492 Me V`.