Atomic weight of boron is 10.81 and it h...

Atomic weight of boron is `10.81` and it has twoisotopes `._(5)^(10)B` and `._(5)^(11)B`. Then, the ratio of atoms of `._(5)^(10) B` and `._(5)^(11)B` in nature would be

`19:81`

`10:11`

`15:16`

`81:19`

Text Solution

Verified by Experts

The correct Answer is:

Let `._(5)^(10)B` and `._(5)^(11)B` be in the ratio `m:n`.
Average atomic weight
`10.81=(mxx10+nxx1)/(m+n)" "rArr(m)/(n)=(0.19)/(0.81)=(19)/(81)`

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