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In a uranium reactor whose thermal power...

In a uranium reactor whose thermal power is `P=100 MW`, if the average number of neutrons liberated in each nuclear spitting is `2.5`. Each splitting is assumed to release an energy `E=200 MeV`. The number of neutrons generated per unit time is-

A

`4xx10^(18)s^(-1)`

B

`8xx10^(19)s^(-1)`

C

`8xx10^(19)s^(-1)`

D

`(125)/(16)xx10^(18)s^(-1)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the number of neutrons generated per unit time in a uranium reactor, given the thermal power, the average number of neutrons released per fission, and the energy released per fission. ### Step-by-Step Solution: 1. **Convert Power to Watts**: The thermal power of the reactor is given as \( P = 100 \, \text{MW} \). \[ P = 100 \, \text{MW} = 100 \times 10^6 \, \text{W} = 10^8 \, \text{W} \] 2. **Convert Energy Released per Fission to Joules**: The energy released per fission is given as \( E = 200 \, \text{MeV} \). To convert MeV to Joules, we use the conversion factor \( 1 \, \text{MeV} = 1.6 \times 10^{-13} \, \text{J} \). \[ E = 200 \, \text{MeV} = 200 \times 1.6 \times 10^{-13} \, \text{J} = 3.2 \times 10^{-11} \, \text{J} \] 3. **Calculate the Number of Fissions per Second**: The number of fissions occurring per second can be calculated using the formula: \[ \text{Number of fissions} = \frac{\text{Power}}{\text{Energy per fission}} = \frac{10^8 \, \text{W}}{3.2 \times 10^{-11} \, \text{J}} \] \[ \text{Number of fissions} = 3.125 \times 10^{18} \, \text{fissions/s} \] 4. **Calculate the Number of Neutrons Generated per Second**: Given that each fission releases an average of \( 2.5 \) neutrons, the total number of neutrons generated per second is: \[ \text{Number of neutrons} = 2.5 \times \text{Number of fissions} \] \[ \text{Number of neutrons} = 2.5 \times 3.125 \times 10^{18} \] \[ \text{Number of neutrons} = 7.8125 \times 10^{18} \, \text{neutrons/s} \] 5. **Final Result**: Therefore, the number of neutrons generated per unit time is approximately: \[ \text{Number of neutrons} \approx 7.81 \times 10^{18} \, \text{neutrons/s} \]

To solve the problem, we need to find the number of neutrons generated per unit time in a uranium reactor, given the thermal power, the average number of neutrons released per fission, and the energy released per fission. ### Step-by-Step Solution: 1. **Convert Power to Watts**: The thermal power of the reactor is given as \( P = 100 \, \text{MW} \). \[ P = 100 \, \text{MW} = 100 \times 10^6 \, \text{W} = 10^8 \, \text{W} ...
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RESONANCE ENGLISH-NUCLEAR PHYSICS-Exercise-1 Part-2 Only one option correct type
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  3. Which of the following processes does not represent a gamma decay ?

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  6. Nuclei X decay into nuclei Y by emitting alpha-aprticles. Energies of ...

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  7. In one average-life,

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  9. Two isotopes P and Q atomic weight 10 and 20, respectively are mixed i...

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  10. Ten grams of ^57 Co kept in an open container beta-decays with a half-...

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  11. A radioactive element P disintegrates into Q which further disintegrat...

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  15. In a uranium reactor whose thermal power is P=100 MW, if the average n...

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  16. Choose the statement which is true.

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  18. in a fission reaction of X and Y is 8.5 MeV , whereas of ""^(236)...

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  19. A heavy nucleus X of mass number 240 and binding energy per nucleon 7....

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  20. Assuming that about 20 MeV of energy is released per fusion reaction ...

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