Find the temperature at which the average kinetic energy of the molecule of hydrogen equals the binding energy of its electron in ground state, assuming average kinetic energy of hydrogen gas molecule `=(3)/(2) kT`.

Answer

`T=(2E_(0))/(3K)=1.05xx10^(5)K`

Explanation

`1.5KT = 13.6 eV`
`T=(13.6xx1.6xx10^(-19))/(1.5xx1.38xx10^(-23))K=1.05xx10^(5)K`