Energy of 24.6 eV is required to remove ...

Energy of 24.6 eV is required to remove one of the electron from a neutral helium atom. The energy (in eV) required to remove both electrons from a neutral helium atom is

`38.2`

`49.2`

`51.8`

`79.0`

Text Solution

Verified by Experts

The correct Answer is:

Energy required to remove the second `e^(-)`
`:. TE=(54.4+24.6)=79.0 eV`.

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