Home
Class 12
PHYSICS
Consider an electron obrbiting the nucle...

Consider an electron obrbiting the nucleus with speed `v` in an orbit of radius `r`. The ratio of the magetic moment to the orbtial angular momentum of the electron is independent of:

A

radius `r`

B

speed `v`

C

charge of electron `e`

D

mass of electron `m_(e )`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the magnetic moment to the orbital angular momentum of an electron orbiting a nucleus. ### Step-by-Step Solution: 1. **Understanding Magnetic Moment**: The magnetic moment (μ) of an electron in orbit can be expressed using the formula: \[ \mu = \frac{e \cdot h}{4 \pi} \] where \( e \) is the charge of the electron and \( h \) is Planck's constant. 2. **Understanding Orbital Angular Momentum**: The orbital angular momentum (L) of the electron can be expressed using the formula: \[ L = m \cdot v \cdot r \] where \( m \) is the mass of the electron, \( v \) is its velocity, and \( r \) is the radius of the orbit. 3. **Finding the Ratio**: We need to find the ratio of the magnetic moment to the orbital angular momentum: \[ \text{Ratio} = \frac{\mu}{L} \] Substituting the expressions for μ and L: \[ \text{Ratio} = \frac{\frac{e \cdot h}{4 \pi}}{m \cdot v \cdot r} \] 4. **Simplifying the Ratio**: This simplifies to: \[ \text{Ratio} = \frac{e \cdot h}{4 \pi \cdot m \cdot v \cdot r} \] Now, we can analyze the components of this ratio. 5. **Identifying Independence**: - The constants \( e \) (charge of the electron), \( h \) (Planck's constant), and \( m \) (mass of the electron) are constants. - The ratio depends on \( v \) (speed of the electron) and \( r \) (radius of the orbit). 6. **Conclusion**: The ratio of the magnetic moment to the orbital angular momentum is independent of: - The radius \( r \) of the orbit. - The speed \( v \) of the electron. - It is dependent on the charge \( e \) of the electron and the mass \( m \) of the electron. ### Final Answer: The ratio of the magnetic moment to the orbital angular momentum of the electron is independent of the radius \( r \) and the speed \( v \).
Promotional Banner

Topper's Solved these Questions

  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Exercise-2 Part-III : Comprehension|12 Videos
  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Exercise -3 part -I JEE (Advanced)|86 Videos
  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Exercise-2 part-II Single and double value integer type|12 Videos
  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise HIGH LEVEL PROBLEMS|11 Videos
  • CAPACITANCE

    RESONANCE ENGLISH|Exercise High Level Problems|16 Videos

Similar Questions

Explore conceptually related problems

the orbital angular momentum of 4f electron is

The orbital angular momentum of 3p electron is :

The orbital angular momentum of a p-electron is given as :

The orbital angular momentum of a p-electron is given as :

The orbital angular momentum of an electron in 2s -orbital is

The orbital angular momentum of an electron in 2s -orbital is

The ratio of magnetic dipole moment to angular momentum of electron is

The orbital angular momentum of an electron in a d-orbital is:

The orbital angular momentum of an electron in 3s-orbital is :

The orbital angular momentum of an electron in 2s orbital is ………